Consider the following species: $CN^{+}$,$CN^{-}$,$NO$,and $CN$. Which one of these will have the highest bond order?

Which of the following statements are correct for the peroxide ion $(O_{2}^{2-})$?
$(i)$ It has a bond order of $1$.
$(ii)$ It is diamagnetic.
$(iii)$ It has four completely filled antibonding molecular orbitals.
$(iv)$ It is isoelectronic with neon.

What is the number of electrons present in antibonding orbitals of $N_2$ molecule according to molecular orbital theory?

Consider the following statements.
$I$. In the conversion of $O_2$ to $O_2^{2+}$,bond order decreases.
$II$. In the conversion of $O_2$ to $O_2^{2+}$,magnetic property is not changed.
$III$. In the conversion of $O_2$ to $O_2^{2+}$,bond length decreases.
$IV$. $O_2^{2-}$ and $B_2$ have same bond order.
Identify the correct statements.

If $Hund's$ Rule does not hold good,then which of the following pairs is diamagnetic?

Which of the following species has the maximum number of unpaired electrons?